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Popular >

extreme 2x^2+16x-4

Solution

extreme points

2 x^{2} + 16 x - 4

Solution

Minimum (- 4, - 36)

Solution steps

f^{'} (x) = 4 x + 16

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < \infty

Plug

x = - 4

into

2 x^{2} + 16 x - 4 : - 36

Minimum (- 4, - 36)

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g (x, y) = 2 x^{2} - y^{2}

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extreme f(x)=(x^2*sqrt(y))/x extreme points

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extreme f(x)=2x^3+3x^2-120x+4,-5<= x<= 5 extreme points

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Frequently Asked Questions (FAQ)

What is the extreme 2x^2+16x-4 ?
The extreme 2x^2+16x-4 is Minimum(-4,-36)