What is the extreme f(x)=3x^2-2x^2-5x+6 ?

The extreme f(x)=3x^2-2x^2-5x+6 is Minimum(5/2 ,-1/4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=3x^2-2x^2-5x+6

extreme points

f (x) = 3 x^{2} - 2 x^{2} - 5 x + 6

Minimum (\frac{5}{2}, - \frac{1}{4})

Solution steps

f^{'} (x) = 2 x - 5

Find intervals:

Decreasing

: - \infty < x < \frac{5}{2},

Increasing

: \frac{5}{2} < x < \infty

Plug

x = \frac{5}{2}

into

3 x^{2} - 2 x^{2} - 5 x + 6 : - \frac{1}{4}

Minimum (\frac{5}{2}, - \frac{1}{4})

f (x) = I n (x + 1 + x^{2})

f (x) = x^{4} - 4 x - 8

f (x) = - 2 x^{3} + 83 x^{2} + 212

f (x) = - x^{3} + 27 - 61

f (x, y) = x^{3} + 3 x y^{2} + x y^{3} - 5 y - 4

What is the extreme f(x)=3x^2-2x^2-5x+6 ?
The extreme f(x)=3x^2-2x^2-5x+6 is Minimum(5/2 ,-1/4)