en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x^2-8x+8

Solution

extreme points

f (x) = 2 x^{2} - 8 x + 8

Solution

Minimum (2, 0)

Solution steps

f^{'} (x) = 4 x - 8

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

2 x^{2} - 8 x + 8 : 0

Minimum (2, 0)

Popular Examples

extreme f(x)=2x^2-8x+4 extreme points

f (x) = 2 x^{2} - 8 x + 4

extreme-(x+4)^5 extreme points

- (x + 4)^{5}

extreme y=ln(x)+x^2 extreme points

y = ln (x) + x^{2}

extreme f(x)=2x^2-8x+1 extreme points

f (x) = 2 x^{2} - 8 x + 1

extreme f(x)=4.5-x-0.25y extreme points

f (x) = 4.5 - x - 0.25 y

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-8x+8 ?
The extreme f(x)=2x^2-8x+8 is Minimum(2,0)