What is the extreme f(x)=7csc(x) ?

The extreme f(x)=7csc(x) is Minimum(pi/2+2pin,7),Maximum((3pi)/2+2pin,-7)

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extreme f(x)=7csc(x)

extreme points

f (x) = 7 csc (x)

Minimum (\frac{π}{2} + 2 πn, 7), Maximum (\frac{3 π}{2} + 2 πn, - 7)

Solution steps

Find the critical points:

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Domain of

7 csc (x) : 2 πn < x < π + 2 πn or π + 2 πn < x < 2 π + 2 πn

Find intervals:

Decreasing

: 2 πn < x < \frac{π}{2} + 2 πn,

Increasing

: \frac{π}{2} + 2 πn < x < π + 2 πn,

Increasing

: π + 2 πn < x < \frac{3 π}{2} + 2 πn,

Decreasing

: \frac{3 π}{2} + 2 πn < x < 2 π + 2 πn

Plug the extreme point

x = \frac{π}{2} + 2 πn

into

7 csc (x) \Rightarrow y = 7

Minimum (\frac{π}{2} + 2 πn, 7)

Plug the extreme point

x = \frac{3 π}{2} + 2 πn

into

7 csc (x) \Rightarrow y = - 7

Maximum (\frac{3 π}{2} + 2 πn, - 7)

Minimum (\frac{π}{2} + 2 πn, 7), Maximum (\frac{3 π}{2} + 2 πn, - 7)

V, V = π r e^{2} \cdot h

f (x) = cos (x) + 2 cos^{2} (x)

(2 y^{2} + x^{2}) e^{- (x^{2} + y^{2} - 3)}

\frac{x ^{5} - 5 x}{5}

f (x) = 12 x - 8

What is the extreme f(x)=7csc(x) ?
The extreme f(x)=7csc(x) is Minimum(pi/2+2pin,7),Maximum((3pi)/2+2pin,-7)