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Popular >

extreme f(x)=2x^2-8x+1

Solution

extreme points

f (x) = 2 x^{2} - 8 x + 1

Solution

Minimum (2, - 7)

Solution steps

f^{'} (x) = 4 x - 8

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

2 x^{2} - 8 x + 1 : - 7

Minimum (2, - 7)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-8x+1 ?
The extreme f(x)=2x^2-8x+1 is Minimum(2,-7)