What is the extreme f(x)=(0.002x^2+24)/x ?

The extreme f(x)=(0.002x^2+24)/x is Maximum(-20sqrt(30),-0.43817…),Minimum(20sqrt(30),0.43817…)

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extreme f(x)=(0.002x^2+24)/x

extreme points

f (x) = \frac{0.002 x ^{2} + 24}{x}

Maximum (- 2030, - 0.43817 \dots), Minimum (2030, 0.43817 \dots)

Solution steps

f^{'} (x) = \frac{0.002 x ^{2} - 24}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 109.54451 \dots,

Decreasing

: - 109.54451 \dots < x < 0,

Decreasing

: 0 < x < 109.54451 \dots,

Increasing

: 109.54451 \dots < x < \infty

Plug

x = - 2030

into

\frac{0.002 x ^{2} + 24}{x} : - 0.43817 \dots

Maximum (- 2030, - 0.43817 \dots)

Plug

x = 2030

into

\frac{0.002 x ^{2} + 24}{x} : 0.43817 \dots

Minimum (2030, 0.43817 \dots)

Maximum (- 2030, - 0.43817 \dots), Minimum (2030, 0.43817 \dots)

f (x, y) = e^{- x^{2} - 3 y^{2} - x + y}

f (x) = - 2 + x - 5 x^{2}

f (x) = 4 sin (x) + 4 cos (x), 0 \leq x \leq 2 π

f (x) = 100 x - (800 + 50 x + 2 x^{2})

\frac{π}{24} sec^{2} (\frac{π x}{24})

What is the extreme f(x)=(0.002x^2+24)/x ?
The extreme f(x)=(0.002x^2+24)/x is Maximum(-20sqrt(30),-0.43817…),Minimum(20sqrt(30),0.43817…)