What is the extreme f(x)=(3x^2+27)/x ?

The extreme f(x)=(3x^2+27)/x is Maximum(-3,-18),Minimum(3,18)

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extreme f(x)=(3x^2+27)/x

extreme points

f (x) = \frac{3 x ^{2} + 27}{x}

Maximum (- 3, - 18), Minimum (3, 18)

Solution steps

f^{'} (x) = \frac{3 x ^{2} - 27}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

\frac{3 x ^{2} + 27}{x} : - 18

Maximum (- 3, - 18)

Plug

x = 3

into

\frac{3 x ^{2} + 27}{x} : 18

Minimum (3, 18)

Maximum (- 3, - 18), Minimum (3, 18)

x ln (9 x)

f (x) = 3 x^{2} + 8, - 4 \leq x \leq 4

f (x) = x (\frac{3600}{x - 4} + 2 \cdot 1 0^{- 3})

f (x) = x^{2} - 18 ln (x)

f (x, y) = 5 x^{2} + 5 y^{2} + 20 x - 10 y

What is the extreme f(x)=(3x^2+27)/x ?
The extreme f(x)=(3x^2+27)/x is Maximum(-3,-18),Minimum(3,18)