What is the extreme f(x)=x^3-12x-1 ?

The extreme f(x)=x^3-12x-1 is Maximum(-2,15),Minimum(2,-17)

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extreme f(x)=x^3-12x-1

extreme points

f (x) = x^{3} - 12 x - 1

Maximum (- 2, 15), Minimum (2, - 17)

Solution steps

f^{'} (x) = 3 x^{2} - 12

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 12 x - 1 : 15

Maximum (- 2, 15)

Plug

x = 2

into

x^{3} - 12 x - 1 : - 17

Minimum (2, - 17)

Maximum (- 2, 15), Minimum (2, - 17)

f (x, y) = 9 - x^{2} - 9 y^{2}

6 sin (x)

2 t^{3} - 24 t^{2} + 70

y = x^{2} e^{x} - 2

f (x, y) = x^{2} + y^{2} + 2 x + 2 y

What is the extreme f(x)=x^3-12x-1 ?
The extreme f(x)=x^3-12x-1 is Maximum(-2,15),Minimum(2,-17)