What is the extreme f(x)=3x^3-9x^2-315x+7 ?

The extreme f(x)=3x^3-9x^2-315x+7 is Maximum(-5,982),Minimum(7,-1610)

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extreme f(x)=3x^3-9x^2-315x+7

extreme points

f (x) = 3 x^{3} - 9 x^{2} - 315 x + 7

Maximum (- 5, 982), Minimum (7, - 1610)

Solution steps

f^{'} (x) = 9 x^{2} - 18 x - 315

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = - 5

into

3 x^{3} - 9 x^{2} - 315 x + 7 : 982

Maximum (- 5, 982)

Plug

x = 7

into

3 x^{3} - 9 x^{2} - 315 x + 7 : - 1610

Minimum (7, - 1610)

Maximum (- 5, 982), Minimum (7, - 1610)

f (x) = \frac{2 x ^{2}}{x - 2}, (- 2, 1)

f (x) = 250 (0.9)^{x}, 0 \leq x \leq 6

y ln (x) + x y^{2}

2 x^{3} - 9 x^{2} + 12 x - 8

f (x) = 4 x^{2} - x y + 2 y^{2}

What is the extreme f(x)=3x^3-9x^2-315x+7 ?
The extreme f(x)=3x^3-9x^2-315x+7 is Maximum(-5,982),Minimum(7,-1610)