What is the extreme f(x)=250(0.9)^x,0<= x<= 6 ?

The extreme f(x)=250(0.9)^x,0<= x<= 6 is Maximum(0,250),Minimum(6,132.86025)

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extreme f(x)=250(0.9)^x,0<= x<= 6

extreme points

f (x) = 250 (0.9)^{x}, 0 \leq x \leq 6

Maximum (0, 250), Minimum (6, 132.86025)

Solution steps

Find the critical points:

x = 0, x = 6

Domain of

2500. 9^{x}, 0 \leq x \leq 6 : 0 \leq x \leq 6

Find intervals:

Decreasing

: 0 < x < 6

Plug the extreme point

x = 0

into

2500. 9^{x} \Rightarrow y = 250

Maximum (0, 250)

Plug the extreme point

x = 6

into

2500. 9^{x} \Rightarrow y = 132.86025

Minimum (6, 132.86025)

Maximum (0, 250), Minimum (6, 132.86025)

y ln (x) + x y^{2}

2 x^{3} - 9 x^{2} + 12 x - 8

f (x) = 4 x^{2} - x y + 2 y^{2}

f (x) = \frac{- 3 x + y - 4}{4 x ^{2} - 3 y + 2}

f (x) = 2 x + 5 x^{- 1}

What is the extreme f(x)=250(0.9)^x,0<= x<= 6 ?
The extreme f(x)=250(0.9)^x,0<= x<= 6 is Maximum(0,250),Minimum(6,132.86025)