What is the extreme 4ap+50p-9p^2-1/10 a^2p-110 ?

The extreme 4ap+50p-9p^2-1/10 a^2p-110 is Maximum(20,5)

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extreme 4ap+50p-9p^2-1/10 a^2p-110

extreme points

4 a p + 50 p - 9 p^{2} - \frac{1}{10} a^{2} p - 110

Maximum (20, 5)

Solution steps

Find the critical points:

(20, 5)

\frac{\partial ^{2} f}{\partial a ^{2}} = - 18

D (a, p) = \frac{18 p + 8 a}{5} - 16 - \frac{a ^{2}}{25}

Check the sign of at each critical point

Check critical point

(20, 5) :

Maximum

Maximum (20, 5)

2 x^{3} + 5 x^{2} + 5 y^{3} - 5 y^{2} + 10

f (x, y) = x^{3} + 3 x^{2} + 6 x y + y^{2}

\frac{( 2 x + 1 )}{( e ^{x^{2}} )}

f (y) = 3 y^{2} - 3 x^{2} - 6 y

f (x, y) = x^{3} y + 12 y x^{2} - 8 y

What is the extreme 4ap+50p-9p^2-1/10 a^2p-110 ?
The extreme 4ap+50p-9p^2-1/10 a^2p-110 is Maximum(20,5)