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Popular >

extreme y=2x^2-5x+4-10

Solution

extreme points

y = 2 x^{2} - 5 x + 4 - 10

Solution

Minimum (\frac{5}{4}, - \frac{73}{8})

Solution steps

f^{'} (x) = 4 x - 5

Find intervals:

Decreasing

: - \infty < x < \frac{5}{4},

Increasing

: \frac{5}{4} < x < \infty

Plug

x = \frac{5}{4}

into

2 x^{2} - 5 x + 4 - 10 : - \frac{73}{8}

Minimum (\frac{5}{4}, - \frac{73}{8})

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extreme f(x,y)=-3y^2+18y-x^2 extreme points

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f (x, y) = 5 x^{2} + 5 x - 2 y + 4 y^{2}

Frequently Asked Questions (FAQ)

What is the extreme y=2x^2-5x+4-10 ?
The extreme y=2x^2-5x+4-10 is Minimum(5/4 ,-73/8)