What is the extreme f(x)=x^4-242x^2+7 ?

The extreme f(x)=x^4-242x^2+7 is Minimum(-11,-14634),Maximum(0,7),Minimum(11,-14634)

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extreme f(x)=x^4-242x^2+7

extreme points

f (x) = x^{4} - 242 x^{2} + 7

Minimum (- 11, - 14634), Maximum (0, 7), Minimum (11, - 14634)

Solution steps

f^{'} (x) = 4 x^{3} - 484 x

Find intervals:

Decreasing

: - \infty < x < - 11,

Increasing

: - 11 < x < 0,

Decreasing

: 0 < x < 11,

Increasing

: 11 < x < \infty

Plug

x = - 11

into

x^{4} - 242 x^{2} + 7 : - 14634

Minimum (- 11, - 14634)

Plug

x = 0

into

x^{4} - 242 x^{2} + 7 : 7

Maximum (0, 7)

Plug

x = 11

into

x^{4} - 242 x^{2} + 7 : - 14634

Minimum (11, - 14634)

Minimum (- 11, - 14634), Maximum (0, 7), Minimum (11, - 14634)

f (x, y) = x^{3} y + 4 x y^{2}

\frac{( x - 2 ) ( 3 - x )}{x ^{2}}

- x^{(2)} - 9

f (x, y) = e^{l n (x^{2} + y^{2})}

f (x) = - 20 x^{2} + 1960 x

What is the extreme f(x)=x^4-242x^2+7 ?
The extreme f(x)=x^4-242x^2+7 is Minimum(-11,-14634),Maximum(0,7),Minimum(11,-14634)