What is the asymptotes of f(x)=(8x^2+1)/(4x^2+2x-6) ?

The asymptotes of f(x)=(8x^2+1)/(4x^2+2x-6) is Vertical: x=-3/2 ,x=1,Horizontal: y=2

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asymptotes of f(x)=(8x^2+1)/(4x^2+2x-6)

asymptotes

f (x) = \frac{8 x ^{2} + 1}{4 x ^{2} + 2 x - 6}

Vertical : x = - \frac{3}{2}, x = 1, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{8 x ^{2} + 1}{4 x ^{2} + 2 x - 6} : x = - \frac{3}{2}, x = 1

Horizontal Asymptotes of

\frac{8 x ^{2} + 1}{4 x ^{2} + 2 x - 6} : y = 2

Slant Asymptotes of

\frac{8 x ^{2} + 1}{4 x ^{2} + 2 x - 6} :

None

Vertical : x = - \frac{3}{2}, x = 1, Horizontal : y = 2

f (x) = - \frac{x}{5} + 3

f (x) = \frac{4}{x + 2}

5 x + 4

y = x (x - 5)

f (x) = - x^{3} - 9 x^{2} - 27 x - 8

What is the asymptotes of f(x)=(8x^2+1)/(4x^2+2x-6) ?
The asymptotes of f(x)=(8x^2+1)/(4x^2+2x-6) is Vertical: x=-3/2 ,x=1,Horizontal: y=2