What is the extreme f(x)=|-3x-2|,-4<x<2 ?

The extreme f(x)=|-3x-2|,-4<x<2 is Minimum(-2/3 ,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=|-3x-2|,-4<x<2

extreme points

f (x) = ∣ - 3 x - 2 ∣, - 4 < x < 2

Minimum (- \frac{2}{3}, 0)

Solution steps

Find the critical points:

x = - \frac{2}{3}

Find intervals:

Decreasing

: - 4 < x < - \frac{2}{3},

Increasing

: - \frac{2}{3} < x < 2

Plug the extreme point

x = - \frac{2}{3}

into

∣ - 3 x - 2 ∣ \Rightarrow y = 0

Minimum (- \frac{2}{3}, 0)

f (x) = 2 + 4 x + 100 x^{- 1}

f (x, y) = x^{2} + y^{2} - 12 x + 16 y

x^{\frac{1}{7}} + 1

f (x) = x^{3} + 6 x^{2} - 6 [- 8.3]

f (x) = \frac{8 ( x ^{2} - 1 )}{3 x ^{\frac{1}{3}}}

What is the extreme f(x)=|-3x-2|,-4<x<2 ?
The extreme f(x)=|-3x-2|,-4<x<2 is Minimum(-2/3 ,0)