What is the extreme y=(x-1)/(x^2+35x) ?

The extreme y=(x-1)/(x^2+35x) is Minimum(-5, 1/25),Maximum(7, 1/49)

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extreme y=(x-1)/(x^2+35x)

extreme points

y = \frac{x - 1}{x ^{2} + 35 x}

Minimum (- 5, \frac{1}{25}), Maximum (7, \frac{1}{49})

Solution steps

f^{'} (x) = \frac{- x ^{2} + 2 x + 35}{( x ^{2} + 35 x ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 35,

Decreasing

: - 35 < x < - 5,

Increasing

: - 5 < x < 0,

Increasing

: 0 < x < 7,

Decreasing

: 7 < x < \infty

Plug

x = - 5

into

\frac{x - 1}{x ^{2} + 35 x} : \frac{1}{25}

Minimum (- 5, \frac{1}{25})

Plug

x = 7

into

\frac{x - 1}{x ^{2} + 35 x} : \frac{1}{49}

Maximum (7, \frac{1}{49})

Minimum (- 5, \frac{1}{25}), Maximum (7, \frac{1}{49})

f (x) = - 3 x^{2} + 12 x - 7

f (x y) = 8 x^{3} + 20 x^{2} y + 40 y^{3}

f (x) = - 6 x - \frac{864}{x}

f (x) = 4 x^{3} + 9 x^{2} - 12 x + 10

f (x) = x^{2} + y^{2} + 8 x - 2 y + 8

What is the extreme y=(x-1)/(x^2+35x) ?
The extreme y=(x-1)/(x^2+35x) is Minimum(-5, 1/25),Maximum(7, 1/49)