What is the extreme f(x)=-20x^2-30y^2+560x+360y+180 ?

The extreme f(x)=-20x^2-30y^2+560x+360y+180 is Maximum(14,6)

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extreme f(x)=-20x^2-30y^2+560x+360y+180

extreme points

f (x) = - 20 x^{2} - 30 y^{2} + 560 x + 360 y + 180

Maximum (14, 6)

Solution steps

Find the critical points:

(14, 6)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 60

D (x, y) = 2400

Check the sign of at each critical point

Check critical point

(14, 6) :

Maximum

Maximum (14, 6)

\frac{3 x + 5}{5 x ^{2} + 55 x + 120}

f (x) = x^{4} e^{- 7 x}

y = 8 + \frac{2}{x}

f (x) = 49 - x^{2}, (- 7, 7)

What is the extreme f(x)=-20x^2-30y^2+560x+360y+180 ?
The extreme f(x)=-20x^2-30y^2+560x+360y+180 is Maximum(14,6)