What is the extreme f(y)=-x^3-5x^2-7x+3 ?

The extreme f(y)=-x^3-5x^2-7x+3 is Minimum(-7/3 , 130/27),Maximum(-1,6)

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extreme f(y)=-x^3-5x^2-7x+3

extreme points

f (y) = - x^{3} - 5 x^{2} - 7 x + 3

Minimum (- \frac{7}{3}, \frac{130}{27}), Maximum (- 1, 6)

Solution steps

f^{'} (x) = - 3 x^{2} - 10 x - 7

Find intervals:

Decreasing

: - \infty < x < - \frac{7}{3},

Increasing

: - \frac{7}{3} < x < - 1,

Decreasing

: - 1 < x < \infty

Plug

x = - \frac{7}{3}

into

- x^{3} - 5 x^{2} - 7 x + 3 : \frac{130}{27}

Minimum (- \frac{7}{3}, \frac{130}{27})

Plug

x = - 1

into

- x^{3} - 5 x^{2} - 7 x + 3 : 6

Maximum (- 1, 6)

Minimum (- \frac{7}{3}, \frac{130}{27}), Maximum (- 1, 6)

f (x) = \frac{7 - x}{6 + x}

f (x, y) = x^{2} - 2 x + 8 y^{2} + 2

x^{3} - 8 x^{2} + 16 x

f (x, y) = 15 x^{2} - 2 x^{3} + 3 y^{2} + 6 x y

4 x^{\frac{3}{4}} - x, 0 \leq x \leq 256

What is the extreme f(y)=-x^3-5x^2-7x+3 ?
The extreme f(y)=-x^3-5x^2-7x+3 is Minimum(-7/3 , 130/27),Maximum(-1,6)