What is the extreme f(x)=x^3-6x^2+9x-7 ?

The extreme f(x)=x^3-6x^2+9x-7 is Maximum(1,-3),Minimum(3,-7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-6x^2+9x-7

extreme points

f (x) = x^{3} - 6 x^{2} + 9 x - 7

Maximum (1, - 3), Minimum (3, - 7)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x + 9

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 1

into

x^{3} - 6 x^{2} + 9 x - 7 : - 3

Maximum (1, - 3)

Plug

x = 3

into

x^{3} - 6 x^{2} + 9 x - 7 : - 7

Minimum (3, - 7)

Maximum (1, - 3), Minimum (3, - 7)

f (x) = 2 x^{5} - x^{4} - 9 x^{3} + 13 x^{2} - 5 x

y = \frac{( x + 1 )}{x ^{2} + 4 x - 5}

f (x) = x (x + 4), x \geq 0

f (x) = 190 + 8 x^{3} + x^{4}

What is the extreme f(x)=x^3-6x^2+9x-7 ?
The extreme f(x)=x^3-6x^2+9x-7 is Maximum(1,-3),Minimum(3,-7)