What is the extreme f(x)=(1)^{1/3}*(-9) ?

The extreme f(x)=(1)^{1/3}*(-9) is None

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extreme f(x)=(1)^{1/3}*(-9)

extreme points

f (x) = (1)^{\frac{1}{3}} \cdot (- 9)

None

Solution steps

Find the critical points:

None

1^{\frac{1}{3}} \cdot (- 9)

has no critical points, therefore there are no extreme points

None

f (x) = - 2 x^{2} - x

f (x) = x^{\frac{2}{3}} (x + 4)

f (x, y, λ) = x^{2} + y^{2} - (x + 2 y - 5)

f (x) = 7 x^{4} - 28 x^{3 + 7}

(\frac{3}{2})^{x}

What is the extreme f(x)=(1)^{1/3}*(-9) ?
The extreme f(x)=(1)^{1/3}*(-9) is None