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Popular >

extreme f(x)=(x^3-1)/(x^3+1)

Solution

extreme points

f (x) = \frac{x ^{3} - 1}{x ^{3} + 1}

Solution

Saddle (0, - 1)

Solution steps

f^{'} (x) = \frac{6 x ^{2}}{( x ^{3} + 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

\frac{x ^{3} - 1}{x ^{3} + 1} : - 1

Saddle (0, - 1)

Popular Examples

extreme f(x,y)=2x^2-5x+6y+2y^2 extreme points

f (x, y) = 2 x^{2} - 5 x + 6 y + 2 y^{2}

extreme f(x)=((-3x^3+8x^2-5x-62))/(x+2)extreme points

f (x) = \frac{( - 3 x ^{3} + 8 x ^{2} - 5 x - 62 )}{x + 2}

extreme f(x)=-0.5x^2+x extreme points

f (x) = - 0.5 x^{2} + x

extreme y=-4x^3+x extreme points

y = - 4 x^{3} + x

extreme f(x)=-2x^2-4 extreme points

f (x) = - 2 x^{2} - 4

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^3-1)/(x^3+1) ?
The extreme f(x)=(x^3-1)/(x^3+1) is Saddle(0,-1)