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Popular >

extreme f(x)=-0.5x^2+x

Solution

extreme points

f (x) = - 0.5 x^{2} + x

Solution

Maximum (1, 0.5)

Solution steps

f^{'} (x) = - x + 1

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 1

into

- 0.5 x^{2} + x : 0.5

Maximum (1, 0.5)

Popular Examples

extreme y=-4x^3+x extreme points

y = - 4 x^{3} + x

extreme f(x)=-2x^2-4 extreme points

f (x) = - 2 x^{2} - 4

extreme y=xsqrt(4-x)extreme points

y = x 4 - x

extreme f(x)=(3x+1)^5(2x+3)^2(2-x)^3 extreme points

f (x) = (3 x + 1)^{5} (2 x + 3)^{2} (2 - x)^{3}

extreme y=2x^3-12x^2-270x+2 extreme points

y = 2 x^{3} - 12 x^{2} - 270 x + 2

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-0.5x^2+x ?
The extreme f(x)=-0.5x^2+x is Maximum(1,0.5)