What is the extreme y=2x^3-12x^2-270x+2 ?

The extreme y=2x^3-12x^2-270x+2 is Maximum(-5,802),Minimum(9,-1942)

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extreme y=2x^3-12x^2-270x+2

extreme points

y = 2 x^{3} - 12 x^{2} - 270 x + 2

Maximum (- 5, 802), Minimum (9, - 1942)

Solution steps

f^{'} (x) = 6 x^{2} - 24 x - 270

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 9,

Increasing

: 9 < x < \infty

Plug

x = - 5

into

2 x^{3} - 12 x^{2} - 270 x + 2 : 802

Maximum (- 5, 802)

Plug

x = 9

into

2 x^{3} - 12 x^{2} - 270 x + 2 : - 1942

Minimum (9, - 1942)

Maximum (- 5, 802), Minimum (9, - 1942)

y = 0.0004 x^{2} - 0.0118 x + 2.6821

x (\frac{8}{5} x^{3} - 2 x^{2})

f (x) = ln (\frac{4 - x}{2 + 2 x})

f (x) = x^{(2)} - 5 x + 4

f (y) = - 0.06 x^{2} - 0.02 y^{2} - 1.5 x y - 85 x + 69 y

What is the extreme y=2x^3-12x^2-270x+2 ?
The extreme y=2x^3-12x^2-270x+2 is Maximum(-5,802),Minimum(9,-1942)