What is the extreme p(t)=500e^{kt} ?

The extreme p(t)=500e^{kt} is Saddle(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme p(t)=500e^{kt}

extreme points

p (t) = 500 e^{k t}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial t ^{2}} = 500 e^{t k} t^{2}

D (t, k) = - 500000 e^{2 t k} t k - 250000 e^{2 t k}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = 400 x^{2} - 1600 x^{3}, 0 \leq x \leq 0.25

f (x) = x y - x^{2} + y^{2} + x + y

y = \frac{1}{2} x^{4} - 4 x^{2} + 3

y = - 4 x^{3} - 6 x^{2} + 360 x - 12