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Popular >

extreme 2x^2-16x+26

Solution

extreme points

2 x^{2} - 16 x + 26

Solution

Minimum (4, - 6)

Solution steps

f^{'} (x) = 4 x - 16

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

2 x^{2} - 16 x + 26 : - 6

Minimum (4, - 6)

Popular Examples

extreme f(x)=Y(x)=x^2-5x+6 extreme points

f (x) = Y (x) = x^{2} - 5 x + 6

extreme f(x)= 1/8 (7x-1),x<= 3 extreme points

f (x) = \frac{1}{8} (7 x - 1), x \leq 3

extreme f(x)=((x^2))/(x^2-4)+2 extreme points

f (x) = \frac{( x ^{2} )}{x ^{2} - 4} + 2

extreme f(x,y)=e^{2-x^2-y^2}extreme points

f (x, y) = e^{2 - x^{2} - y^{2}}

extreme f(x)=-12x^2+100 extreme points

f (x) = - 12 x^{2} + 100

Frequently Asked Questions (FAQ)

What is the extreme 2x^2-16x+26 ?
The extreme 2x^2-16x+26 is Minimum(4,-6)