What is the extreme f(x,y)=3xy+6y-5x ?

The extreme f(x,y)=3xy+6y-5x is Saddle(-2, 5/3)

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extreme f(x,y)=3xy+6y-5x

extreme points

f (x, y) = 3 x y + 6 y - 5 x

Saddle (- 2, \frac{5}{3})

Solution steps

Find the critical points:

(- 2, \frac{5}{3})

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 9

Check the sign of at each critical point

Check critical point

(- 2, \frac{5}{3}) :

Saddle

Saddle (- 2, \frac{5}{3})

y = I n ∣ 1 - x ∣

f (x) = - 2 x^{2} + 3 x y - 9 x

f (x) = 36 - t^{2}

- x^{3} + 2 x^{2} + 4 x + 7

f (x) = 2 x^{3} - 39 x^{2} + 180 x + 1

What is the extreme f(x,y)=3xy+6y-5x ?
The extreme f(x,y)=3xy+6y-5x is Saddle(-2, 5/3)