What is the extreme f(x)=120x-x^2-(950+14x) ?

The extreme f(x)=120x-x^2-(950+14x) is Maximum(53,1859)

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extreme f(x)=120x-x^2-(950+14x)

extreme points

f (x) = 120 x - x^{2} - (950 + 14 x)

Maximum (53, 1859)

Solution steps

f^{'} (x) = - 2 x + 106

Find intervals:

Increasing

: - \infty < x < 53,

Decreasing

: 53 < x < \infty

Plug

x = 53

into

120 x - x^{2} - (950 + 14 x) : 1859

Maximum (53, 1859)

f (x) = \frac{x ^{3}}{3} - 3 x^{2} + 8 x - 2

f (x) = \frac{x ^{3}}{3} - 3 x^{2} + 8 x - 4

f (x) = x^{4} + \frac{4}{3 x ^{3}}

f (x) = 3 x^{2} - 18 x + 5

f (x) = \frac{7}{4} x^{2} - \frac{21}{2} x - \frac{43}{3}

What is the extreme f(x)=120x-x^2-(950+14x) ?
The extreme f(x)=120x-x^2-(950+14x) is Maximum(53,1859)