What is the extreme f(x)= 7/4 x^2-21/2 x-43/3 ?

The extreme f(x)= 7/4 x^2-21/2 x-43/3 is Minimum(3,-361/12)

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extreme f(x)= 7/4 x^2-21/2 x-43/3

extreme points

f (x) = \frac{7}{4} x^{2} - \frac{21}{2} x - \frac{43}{3}

Minimum (3, - \frac{361}{12})

Solution steps

f^{'} (x) = \frac{7 x - 21}{2}

Find intervals:

Decreasing

: - \infty < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 3

into

\frac{7}{4} x^{2} - \frac{21}{2} x - \frac{43}{3} : - \frac{361}{12}

Minimum (3, - \frac{361}{12})

x \cdot e^{- x^{2} + 1}

330 x^{2} - 1320 x^{3}

f (x) = \frac{∣ x - 3 ∣}{x ^{2} - 9}

y = x^{4} ln (\frac{x}{10})

f (x) = \frac{18}{( x ^{2} - 9 )}

What is the extreme f(x)= 7/4 x^2-21/2 x-43/3 ?
The extreme f(x)= 7/4 x^2-21/2 x-43/3 is Minimum(3,-361/12)