What is the extreme f(x)=7x-28sqrt(x) ?

The extreme f(x)=7x-28sqrt(x) is Minimum(0,0),Minimum(4,-28)

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extreme f(x)=7x-28sqrt(x)

extreme points

f (x) = 7 x - 28 x

Minimum (0, 0), Minimum (4, - 28)

Solution steps

f^{'} (x) = 7 - \frac{14}{x}

Find intervals:

Increasing

: 0 \leq x < \frac{1}{4},

Decreasing

: \frac{1}{4} < x < \infty

Plug

x = 0

into

7 x - 28 x : 0

Minimum (0, 0)

Plug

x = 4

into

7 x - 28 x : - 28

Minimum (4, - 28)

Minimum (0, 0), Minimum (4, - 28)

f (x) = ((x y) - λ (6 x + y - 20))

y = \frac{x + 3}{2}

f (x, y) = 3 x^{2} - x y + y^{2} - 11 x

f (x, y) = (x - 1)^{2} - (y - 1)^{2}

f (x, y) = x^{2} + y^{2} + 2 x - 18 y

What is the extreme f(x)=7x-28sqrt(x) ?
The extreme f(x)=7x-28sqrt(x) is Minimum(0,0),Minimum(4,-28)