What is the extreme f(x,y)=x^2+y^2+2x-18y ?

The extreme f(x,y)=x^2+y^2+2x-18y is Minimum(-1,9)

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extreme f(x,y)=x^2+y^2+2x-18y

extreme points

f (x, y) = x^{2} + y^{2} + 2 x - 18 y

Minimum (- 1, 9)

Solution steps

Find the critical points:

(- 1, 9)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(- 1, 9) :

Minimum

Minimum (- 1, 9)

f (x) = 161000 x - 100 x^{21}

f (x) = - 6 x^{2} e^{- x} - 4

f (x) = 2.2 + 2.6 x - 0.8 x^{2}

f (x) = - 4 x^{3} + 12 x^{2} + 36 + 3

f (x) = 3^{\frac{2}{3}} - 2 x (- 1.1)

What is the extreme f(x,y)=x^2+y^2+2x-18y ?
The extreme f(x,y)=x^2+y^2+2x-18y is Minimum(-1,9)