What is the extreme f(x)=2.2+2.6x-0.8x^2 ?

The extreme f(x)=2.2+2.6x-0.8x^2 is Maximum(13/8 ,4.3125)

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extreme f(x)=2.2+2.6x-0.8x^2

extreme points

f (x) = 2.2 + 2.6 x - 0.8 x^{2}

Maximum (\frac{13}{8}, 4.3125)

Solution steps

f^{'} (x) = - 1.6 x + 2.6

Find intervals:

Increasing

: - \infty < x < \frac{13}{8},

Decreasing

: \frac{13}{8} < x < \infty

Plug

x = \frac{13}{8}

into

2.2 + 2.6 x - 0.8 x^{2} : 4.3125

Maximum (\frac{13}{8}, 4.3125)

f (x) = - 4 x^{3} + 12 x^{2} + 36 + 3

f (x) = 3^{\frac{2}{3}} - 2 x (- 1.1)

f (x) = - 0.001 x^{2} + 6 x - 1900

h (x) = 5 (x - 1)^{\frac{2}{3}}, 0 \leq x \leq 2

f (x) = - 4 x^{3} + 6 x^{2} + 6

What is the extreme f(x)=2.2+2.6x-0.8x^2 ?
The extreme f(x)=2.2+2.6x-0.8x^2 is Maximum(13/8 ,4.3125)