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Popular >

extreme ((x-4))/(x^2)

Solution

extreme points

\frac{( x - 4 )}{x ^{2}}

Solution

Maximum (8, \frac{1}{16})

Solution steps

f^{'} (x) = \frac{- x + 8}{x ^{3}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 8,

Decreasing

: 8 < x < \infty

Plug

x = 8

into

\frac{x - 4}{x ^{2}} : \frac{1}{16}

Maximum (8, \frac{1}{16})

Popular Examples

extreme f(x)=(2x-6)/(sqrt(x^2+7)-4)extreme points

f (x) = \frac{2 x - 6}{x ^{2} + 7 - 4}

extreme f(x)=(5+x)+(1000+100x)extreme points

f (x) = (5 + x) + (1000 + 100 x)

extreme f(x)=-(x/3)^3+2x^2+12x+1 extreme points

f (x) = - (\frac{x}{3})^{3} + 2 x^{2} + 12 x + 1

extreme y=5+6x-8x^3 extreme points

y = 5 + 6 x - 8 x^{3}

extreme f(x)=(2x+4)/(x^2+4)extreme points

f (x) = \frac{2 x + 4}{x ^{2} + 4}

Frequently Asked Questions (FAQ)

What is the extreme ((x-4))/(x^2) ?
The extreme ((x-4))/(x^2) is Maximum(8, 1/16)