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Popular >

extreme y=2x^2+5

Solution

extreme points

y = 2 x^{2} + 5

Solution

Minimum (0, 5)

Solution steps

f^{'} (x) = 4 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

2 x^{2} + 5 : 5

Minimum (0, 5)

Popular Examples

extreme f(x)=5x^4-20x^3+1 extreme points

f (x) = 5 x^{4} - 20 x^{3} + 1

extreme f(x)=0.001x^2+3.2x-10 extreme points

f (x) = 0.001 x^{2} + 3.2 x - 10

extreme f(x,y)=x^2+y^2-2x-4y extreme points

f (x, y) = x^{2} + y^{2} - 2 x - 4 y

extreme f(x)=-7x^2-7xy-6y^2-35x-26y+9 extreme points

f (x) = - 7 x^{2} - 7 x y - 6 y^{2} - 35 x - 26 y + 9

extreme 3(x-4)^{2/3}+6 extreme points

3 (x - 4)^{\frac{2}{3}} + 6

Frequently Asked Questions (FAQ)

What is the extreme y=2x^2+5 ?
The extreme y=2x^2+5 is Minimum(0,5)