What is the extreme f(x)=-7x^2-7xy-6y^2-35x-26y+9 ?

The extreme f(x)=-7x^2-7xy-6y^2-35x-26y+9 is Maximum(-2,-1)

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extreme f(x)=-7x^2-7xy-6y^2-35x-26y+9

extreme points

f (x) = - 7 x^{2} - 7 x y - 6 y^{2} - 35 x - 26 y + 9

Maximum (- 2, - 1)

Solution steps

Find the critical points:

(- 2, - 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 12

D (x, y) = 119

Check the sign of at each critical point

Check critical point

(- 2, - 1) :

Maximum

Maximum (- 2, - 1)

3 (x - 4)^{\frac{2}{3}} + 6

y = x^{3} + 3 x^{2}

f (x) = 4 x^{\frac{3}{5}}

f (x) = x - (\frac{x}{y}) \cdot y

f (x) = 6 x^{3} + 27 x^{2} - 180 x

What is the extreme f(x)=-7x^2-7xy-6y^2-35x-26y+9 ?
The extreme f(x)=-7x^2-7xy-6y^2-35x-26y+9 is Maximum(-2,-1)