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Popular >

extreme f(x)=x^2+6

Solution

extreme points

f (x) = x^{2} + 6

Solution

Minimum (0, 6)

Solution steps

f^{'} (x) = 2 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{2} + 6 : 6

Minimum (0, 6)

Popular Examples

extreme f(x)=6sqrt(x^2+1)-x,0<= x<= 3 extreme points

f (x) = 6 x^{2} + 1 - x, 0 \leq x \leq 3

extreme f(x)=x^2-x-5 extreme points

f (x) = x^{2} - x - 5

extreme 5x^3+67.5x^2+2x+10 extreme points

5 x^{3} + 67.5 x^{2} + 2 x + 10

extreme f(x)=25x^2-x^3 extreme points

f (x) = 25 x^{2} - x^{3}

extreme f(x)=4x^2-16x+20 extreme points

f (x) = 4 x^{2} - 16 x + 20

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+6 ?
The extreme f(x)=x^2+6 is Minimum(0,6)