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Popular >

extreme f(x)=x^2-x-5

Solution

extreme points

f (x) = x^{2} - x - 5

Solution

Minimum (\frac{1}{2}, - \frac{21}{4})

Solution steps

f^{'} (x) = 2 x - 1

Find intervals:

Decreasing

: - \infty < x < \frac{1}{2},

Increasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

x^{2} - x - 5 : - \frac{21}{4}

Minimum (\frac{1}{2}, - \frac{21}{4})

Popular Examples

extreme 5x^3+67.5x^2+2x+10 extreme points

5 x^{3} + 67.5 x^{2} + 2 x + 10

extreme f(x)=25x^2-x^3 extreme points

f (x) = 25 x^{2} - x^{3}

extreme f(x)=4x^2-16x+20 extreme points

f (x) = 4 x^{2} - 16 x + 20

extreme g(x)=-50x^2+400x+500 extreme points

g (x) = - 50 x^{2} + 400 x + 500

extreme f(x)=4x+5y extreme points

f (x) = 4 x + 5 y

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-x-5 ?
The extreme f(x)=x^2-x-5 is Minimum(1/2 ,-21/4)