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Popular >

extreme x^2-8x+15

Solution

extreme points

x^{2} - 8 x + 15

Solution

Minimum (4, - 1)

Solution steps

f^{'} (x) = 2 x - 8

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

x^{2} - 8 x + 15 : - 1

Minimum (4, - 1)

Popular Examples

extreme x^2-8x+13 extreme points

x^{2} - 8 x + 13

extreme f(x)=2x^2-5x+2 extreme points

f (x) = 2 x^{2} - 5 x + 2

extreme f(x)= x/(ln(x))[2.1]extreme points

f (x) = \frac{x}{ln ( x )} [2.1]

extreme f(x)=x^4-72x^2-2,-7<= x<= 7 extreme points

f (x) = x^{4} - 72 x^{2} - 2, - 7 \leq x \leq 7

extreme f(x)=x^2+10x^{2/3}extreme points

f (x) = x^{2} + 10 x^{\frac{2}{3}}

Frequently Asked Questions (FAQ)

What is the extreme x^2-8x+15 ?
The extreme x^2-8x+15 is Minimum(4,-1)