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Popular >

extreme (7e^x+7e^{-x})/2

Solution

extreme points

\frac{7 e ^{x} + 7 e ^{- x}}{2}

Solution

Minimum (0, 7)

Solution steps

f^{'} (x) = \frac{1}{2} (7 e^{x} - 7 e^{- x})

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

\frac{7 e ^{x} + 7 e ^{- x}}{2} : 7

Minimum (0, 7)

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Frequently Asked Questions (FAQ)

What is the extreme (7e^x+7e^{-x})/2 ?
The extreme (7e^x+7e^{-x})/2 is Minimum(0,7)