What is the extreme f(x)=3-4x-5x^2[-2.4] ?

The extreme f(x)=3-4x-5x^2[-2.4] is Minimum(1/6 ,2.66666…)

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extreme f(x)=3-4x-5x^2[-2.4]

extreme points

f (x) = 3 - 4 x - 5 x^{2} [- 2.4]

Minimum (\frac{1}{6}, 2.66666 \dots)

Solution steps

f^{'} (x) = 24 x - 4

Find intervals:

Decreasing

: - \infty < x < \frac{1}{6},

Increasing

: \frac{1}{6} < x < \infty

Plug

x = \frac{1}{6}

into

3 - 4 x - 5 x^{2} [- 2.4] : 2.66666 \dots

Minimum (\frac{1}{6}, 2.66666 \dots)

f (x) = \frac{x + 2}{( x + 1 ) ( 2 - x )}

4 + \frac{9 x - 36}{( x - 4 ) ^{2} + 65}

f (x) = \frac{- 125}{4} x^{4} + x

f (x) = ln (x^{2} - 6 x - 7)

f (x) = sin (2 π x)

What is the extreme f(x)=3-4x-5x^2[-2.4] ?
The extreme f(x)=3-4x-5x^2[-2.4] is Minimum(1/6 ,2.66666…)