What is the extreme f(x)=x^3-8x^2-12x+5 ?

The extreme f(x)=x^3-8x^2-12x+5 is Maximum(-2/3 , 247/27),Minimum(6,-139)

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extreme f(x)=x^3-8x^2-12x+5

extreme points

f (x) = x^{3} - 8 x^{2} - 12 x + 5

Maximum (- \frac{2}{3}, \frac{247}{27}), Minimum (6, - 139)

Solution steps

f^{'} (x) = 3 x^{2} - 16 x - 12

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 6,

Increasing

: 6 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 8 x^{2} - 12 x + 5 : \frac{247}{27}

Maximum (- \frac{2}{3}, \frac{247}{27})

Plug

x = 6

into

x^{3} - 8 x^{2} - 12 x + 5 : - 139

Minimum (6, - 139)

Maximum (- \frac{2}{3}, \frac{247}{27}), Minimum (6, - 139)

f (x) = x^{3} - 8 x^{2} - 12 x + 9

f (x, y) = (2 x - x^{(2)}) (2 y - y^{(2)})

f (x) = 8 + (9 + 7 x)^{\frac{2}{7}}

f (x) = 6 x + 7 y

f (x, y) = x y - 3 x^{3} y^{2}

What is the extreme f(x)=x^3-8x^2-12x+5 ?
The extreme f(x)=x^3-8x^2-12x+5 is Maximum(-2/3 , 247/27),Minimum(6,-139)