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Popular Functions >

extreme f(x)=12x^2-18x

Solution

extreme

Solution

Minimum (\frac{3}{4}, - \frac{27}{4})

Solution steps

f^{'} (x) = 24 x - 18

Find intervals:

Decreasing

: - \infty < x < \frac{3}{4},

Increasing

: \frac{3}{4} < x < \infty

Plug

x = \frac{3}{4}

into

12 x^{2} - 18 x : - \frac{27}{4}

Minimum (\frac{3}{4}, - \frac{27}{4})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=12x^2-18x ?
The extreme f(x)=12x^2-18x is Minimum(3/4 ,-27/4)