What is the extreme f(x)=3x+(147)/x ?

The extreme f(x)=3x+(147)/x is Maximum(-7,-42),Minimum(7,42)

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extreme f(x)=3x+(147)/x

extreme points

f (x) = 3 x + \frac{147}{x}

Maximum (- 7, - 42), Minimum (7, 42)

Solution steps

f^{'} (x) = 3 - \frac{147}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 7,

Decreasing

: - 7 < x < 0,

Decreasing

: 0 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = - 7

into

3 x + \frac{147}{x} : - 42

Maximum (- 7, - 42)

Plug

x = 7

into

3 x + \frac{147}{x} : 42

Minimum (7, 42)

Maximum (- 7, - 42), Minimum (7, 42)

f (x, y) = x^{(2)} + y^{(2)} + x^{(2)} y + 4

2 cos (x) + 2 sin (x)

f (x) = \frac{8}{x ^{2} - 4}

\frac{3 ( x - 7 ) ( x - 6 )}{3 ( x - 7 )}

f (x) = x^{3} + x + 1

What is the extreme f(x)=3x+(147)/x ?
The extreme f(x)=3x+(147)/x is Maximum(-7,-42),Minimum(7,42)