What is the extreme f(x)=cos(x)[-pi/4 , pi/4 ] ?

The extreme f(x)=cos(x)[-pi/4 , pi/4 ] is None

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extreme f(x)=cos(x)[-pi/4 , pi/4 ]

extreme points

f (x) = cos (x) [- \frac{π}{4}, \frac{π}{4}]

None

Solution steps

Find the critical points:

None

cos (x) [- \frac{π}{4}, \frac{π}{4}]

has no critical points, therefore there are no extreme points

None

f (x) = x^{2} - x + \frac{9}{4}

f (x) = \frac{12}{6 - x} - \frac{x}{3} + 8

y = - 2 x^{2} + 12 x - 8

f (x) = x^{3} - 3 x^{2} - 9 x + 6

f (x, y) = ln (4 x^{2} + 9 y^{2} - 36)

What is the extreme f(x)=cos(x)[-pi/4 , pi/4 ] ?
The extreme f(x)=cos(x)[-pi/4 , pi/4 ] is None