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Popular >

extreme f(x)=3x^2-4x+12

Solution

extreme points

f (x) = 3 x^{2} - 4 x + 12

Solution

Minimum (\frac{2}{3}, \frac{32}{3})

Solution steps

f^{'} (x) = 6 x - 4

Find intervals:

Decreasing

: - \infty < x < \frac{2}{3},

Increasing

: \frac{2}{3} < x < \infty

Plug

x = \frac{2}{3}

into

3 x^{2} - 4 x + 12 : \frac{32}{3}

Minimum (\frac{2}{3}, \frac{32}{3})

Popular Examples

extreme f(x)=x(-(2x)/3+4)extreme points

f (x) = x (- \frac{2 x}{3} + 4)

extreme f(x,y)=2x^2+3y^2+2xy-6x-8y+11 extreme points

f (x, y) = 2 x^{2} + 3 y^{2} + 2 x y - 6 x - 8 y + 11

extreme f(x,y)=x^2-2xy+1/3 y^3-4y extreme points

f (x, y) = x^{2} - 2 x y + \frac{1}{3} y^{3} - 4 y

extreme f(x)=4x^5-25x^4+40x^3-4[-1.4]extreme points

f (x) = 4 x^{5} - 25 x^{4} + 40 x^{3} - 4 [- 1.4]

extreme f(x)=-1/2 x^2+15x-51 extreme points

f (x) = - \frac{1}{2} x^{2} + 15 x - 51

Frequently Asked Questions (FAQ)

What is the extreme f(x)=3x^2-4x+12 ?
The extreme f(x)=3x^2-4x+12 is Minimum(2/3 , 32/3)