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Popular >

extreme f(x)=9t^2+4t-10

Solution

extreme points

f (x) = 9 t^{2} + 4 t - 10

Solution

Minimum (- \frac{2}{9}, - \frac{94}{9})

Solution steps

f^{'} (t) = 18 t + 4

Find intervals:

Decreasing

: - \infty < t < - \frac{2}{9},

Increasing

: - \frac{2}{9} < t < \infty

Plug

t = - \frac{2}{9}

into

9 t^{2} + 4 t - 10 : - \frac{94}{9}

Minimum (- \frac{2}{9}, - \frac{94}{9})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=9t^2+4t-10 ?
The extreme f(x)=9t^2+4t-10 is Minimum(-2/9 ,-94/9)