What is the extreme f(x)=-2^3-3*(-2^2)+3*(-2)+1 ?

The extreme f(x)=-2^3-3*(-2^2)+3*(-2)+1 is None

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-2^3-3(-2^2)+3(-2)+1

extreme points

f (x) = - 2^{3} - 3 \cdot (- 2^{2}) + 3 \cdot (- 2) + 1

None

Solution steps

Find the critical points:

None

- 2^{3} - 3 \cdot (- 2^{2}) + 3 \cdot (- 2) + 1

has no critical points, therefore there are no extreme points

None

g (x) = e^{- x^{4}}, - 3 \leq x \leq 1

f (x, y) = x^{2} + y^{2} - 4 x + 3 y

f (x, y) = 2^{3} - y^{2} + 2 x y + 1

y = x^{2} + 2

f (x) = 2^{(x + 0.528)} - 10 (x + 0.528)

What is the extreme f(x)=-2^3-3*(-2^2)+3*(-2)+1 ?
The extreme f(x)=-2^3-3*(-2^2)+3*(-2)+1 is None