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Popular >

extreme f(x)=(1-x^2)/(x^2+1)

Solution

extreme points

f (x) = \frac{1 - x ^{2}}{x ^{2} + 1}

Solution

Maximum (0, 1)

Solution steps

f^{'} (x) = - \frac{4 x}{( x ^{2} + 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

\frac{1 - x ^{2}}{x ^{2} + 1} : 1

Maximum (0, 1)

Popular Examples

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2 t^{2} + 7 t + 9

extreme f(x)=6xsqrt(16-x^2)extreme points

f (x) = 6 x 16 - x^{2}

extreme f(x)=6x^2-40x+50 extreme points

f (x) = 6 x^{2} - 40 x + 50

extreme y=(x^2+9)/(x^2-64)extreme points

y = \frac{x ^{2} + 9}{x ^{2} - 64}

extreme f(x)=5x+8y extreme points

f (x) = 5 x + 8 y

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(1-x^2)/(x^2+1) ?
The extreme f(x)=(1-x^2)/(x^2+1) is Maximum(0,1)