What is the extreme f(x)=2x^3+3x^2-120x+9 ?

The extreme f(x)=2x^3+3x^2-120x+9 is Maximum(-5,434),Minimum(4,-295)

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extreme f(x)=2x^3+3x^2-120x+9

extreme points

f (x) = 2 x^{3} + 3 x^{2} - 120 x + 9

Maximum (- 5, 434), Minimum (4, - 295)

Solution steps

f^{'} (x) = 6 x^{2} + 6 x - 120

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 5

into

2 x^{3} + 3 x^{2} - 120 x + 9 : 434

Maximum (- 5, 434)

Plug

x = 4

into

2 x^{3} + 3 x^{2} - 120 x + 9 : - 295

Minimum (4, - 295)

Maximum (- 5, 434), Minimum (4, - 295)

f (x) = x^{3} + 12 x^{2} - 27 x + 6, - 10 \leq x \leq 0

y = (2 x^{2} - 1)^{2}

f (x) = \frac{6}{- 4 x + 2}

f (y) = x^{y + 1}

f (x) = x^{2} lo g_{8} (x)

What is the extreme f(x)=2x^3+3x^2-120x+9 ?
The extreme f(x)=2x^3+3x^2-120x+9 is Maximum(-5,434),Minimum(4,-295)