What is the extreme f(x)=28x-(x^2)/(105) ?

The extreme f(x)=28x-(x^2)/(105) is Maximum(1470,20580)

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extreme f(x)=28x-(x^2)/(105)

extreme points

f (x) = 28 x - \frac{x ^{2}}{105}

Maximum (1470, 20580)

Solution steps

f^{'} (x) = 28 - \frac{2 x}{105}

Find intervals:

Increasing

: - \infty < x < 1470,

Decreasing

: 1470 < x < \infty

Plug

x = 1470

into

28 x - \frac{x ^{2}}{105} : 20580

Maximum (1470, 20580)

3^{x - 1}

f (x) = 1 + sec^{2} (x)

f (x) = x^{4} - 8 x^{2} + 9

f (x) = ln (5 x^{2} - 4 x - 3)

f (x) = x^{- 2} - 13 x^{- 1}

What is the extreme f(x)=28x-(x^2)/(105) ?
The extreme f(x)=28x-(x^2)/(105) is Maximum(1470,20580)