What is the extreme f(x,y)=y(e^x-1) ?

The extreme f(x,y)=y(e^x-1) is Saddle(0,0)

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extreme f(x,y)=y(e^x-1)

extreme points

f (x, y) = y (e^{x} - 1)

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - e^{2 x}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

y = \frac{5 x ^{2}}{( x - 4 ) ^{2}}

f (x) = x (x - 10)^{2}

5 x^{4} - x^{5} + 4

f (x) = x^{2} + 2 y + y^{2} - 8

f (x) = x 3 x - x^{2}

What is the extreme f(x,y)=y(e^x-1) ?
The extreme f(x,y)=y(e^x-1) is Saddle(0,0)